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A thin piece of cable 90 meters long is cut into two pieces.

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A thin piece of cable 90 meters long is cut into two pieces. One piece is used to form a square with diagonal \sqrt{72}, and the other is used to form a equilateral triangle. 6 meters cable is left over. The total area, in square meters, of the square and equilateral triangle regions would be

A: 24 + 100\sqrt{3}

B: 36 + 20\sqrt{3}

C: 36 + 50\sqrt{3}

D: \sqrt{3}(100 + 12\sqrt{3})

E: 42 + 100\sqrt{3}

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