A thin piece of cable 90 meters long is cut into two pieces. One piece is used to form a square with diagonal \sqrt{72}, and the other is used to form a equilateral triangle. 6 meters cable is left over. The total area, in square meters, of the square and equilateral triangle regions would be
A: 24 + 100\sqrt{3}
B: 36 + 20\sqrt{3}
C: 36 + 50\sqrt{3}
D: \sqrt{3}(100 + 12\sqrt{3})
E: 42 + 100\sqrt{3}
A: 24 + 100\sqrt{3}
B: 36 + 20\sqrt{3}
C: 36 + 50\sqrt{3}
D: \sqrt{3}(100 + 12\sqrt{3})
E: 42 + 100\sqrt{3}