Two circles with equal radius pass through centre of each other as shown in figure. If radius = r, the area of the overlapping region would be:
A: 2\pi r^2 - \frac{\sqrt{3}}{2}
B: 2\pi r^2 - \frac{\pi}{8}
C: r^2(\frac{4\pi}{3} - \frac{\sqrt{3}}{4})
D: r^2(\frac{\pi}{3} - \sqrt{2})
E: r^2(\frac{2\pi}{3} - \frac{\sqrt{3}}{2})![]()
Attachment:
Circle.jpg
A: 2\pi r^2 - \frac{\sqrt{3}}{2}
B: 2\pi r^2 - \frac{\pi}{8}
C: r^2(\frac{4\pi}{3} - \frac{\sqrt{3}}{4})
D: r^2(\frac{\pi}{3} - \sqrt{2})
E: r^2(\frac{2\pi}{3} - \frac{\sqrt{3}}{2})