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A company has 11 comp engg and 7 mech engg. In how many ways can they

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A company has 11 comp engg and 7 mech engg. In how many ways can they be seated
around a round table so that all mech engg dont sit together.

a.17!-(11! x 6!)
b.17!-(11! x 7!)




My sol -- all never together = total permutation - all mech engg together

i.e. 17! - (6! x 11!)

Please give your explanations.

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