Q. How many roots does the equation ||x+2|2|=2 have?
a. 0
b. 1
c. 2
d. 3
3. 4
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a. 0
b. 1
c. 2
d. 3
3. 4
I am okay with the solution given for the above problem but I tried solving by solving algebraically and I missed out on one of the roots.
||x+2|2|=2----->>Can be re-written as
\sqrt{({| {|x+2|}{2}|)^{2}} = 2
Squaring both sides we get
(||x+2|2|)^2 = 4
Now |x+2| is positive so the expression can be written as ((x+2)-2)^2= 4 or x^2=4 or x=-2 or 2
How do I get -6 (another root) which should be there actually...Did I do anything wrong above.
PS: Looked on the forum before but could not find anything so posting it here.
||x+2|2|=2----->>Can be re-written as
\sqrt{({| {|x+2|}{2}|)^{2}} = 2
Squaring both sides we get
(||x+2|2|)^2 = 4
Now |x+2| is positive so the expression can be written as ((x+2)-2)^2= 4 or x^2=4 or x=-2 or 2
How do I get -6 (another root) which should be there actually...Did I do anything wrong above.
PS: Looked on the forum before but could not find anything so posting it here.