Does integer n have 2 factors x & y such that 1 < x < y < n?

(1): 3! < n < 4! 6 < n < 24. Every even integer can be expressed as a multiple of 2, all even numbers in range will give us a "yes" to question.
However, since primes are in range (7, 11, 13, 17, 19, 23), that cannot be factored further than itself, we can also answer question "no."
If n = 8, it has 2 integer factors 2 and 4 that fit criteria: 1 < 2 < 4 < 8 "yes"
If n = 7, it cannot be broken down into factors that fit criteria of question "no"
Insufficient
(2): Any positive, odd multiple of 3 is a possible value for n. For larger multiples of 3, we can easily fit criteria, giving "yes" answer. However, since any numbers smallest multiple is itself, 3 is a possible value for n that would not fit criteria, giving "no."
If n = 15, we can factor it as 3 and 5, and we fit criteria: 1< 3 < 5 < 15 "yes"
If n = 9, we can only factor it as 3 and 3, which does not fit criteria "no"
Insufficient
Combined: (1) limits possible values of n to those integers between 6 and 24. (2) adds limitation that n be odd multiple of 3. Possible values for n = (9, 15 and 21)
If n = 9, we answer question "no,"
If n = 15 or 21, we can answer question "yes."
Insufficient