Three dice are thrown. What is the probability that the first two show the same number, and the last one a different number?
A. 3/6
B. 15/36
C.1/216
D. 15/216
E. 1/6
So I did 1/6 * 1/6 * 5/6 (first two show the same number, the last one another number) = 5/216. then i multiply by 3 and get 15/216.
whats wrong with what I did?
OA:![]()
A. 3/6
B. 15/36
C.1/216
D. 15/216
E. 1/6
So I did 1/6 * 1/6 * 5/6 (first two show the same number, the last one another number) = 5/216. then i multiply by 3 and get 15/216.
whats wrong with what I did?
OA:
[Reveal] Spoiler:
B